The floor of a room is 6 m long and 4.2 m wide. It has a border of 20 cm laid with
green marble. The remaining floor has a white marble. Find the area covered with green
and white marbles separately.
Answers
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Dear Student,
◆ Answer -
White marble = 23.2 sq.m
Green marble = 2 sq.m
● Explanation -
# Given -
L = 6 m
B = 4.2 m
t = 20 cm = 0.2 m
l = 6-0.2 = 5.8 m
b = 4.2-0.2 = 4 m
# Solution -
Area covered by white marble iz -
White marble = area of inner rectangle
White marble = l × b
White marble = 5.8 × 4
White marble = 23.2 sq.m
Area covered by green marble is -
Green marble = area of outer rectangle - area of innner rectangle
Green marble = L×B - l×b
Green marble = 6×4.2 - 5.8×4
Green marble = 2 sq.m
Hope this helps you..
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