The floor of a room is 8 M 40 cm long and 7 M 56 CM broad find the minimum number of square tiles of the same size needed to cover the entire room
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8m 96cm = 8 × 100 + 96 = 896 cm
6m 72cm = 6 × 100 + 72 = 672 cm
Side of largest square tile that can be used = HCF of 896 and 672 = 224 cm
Area of the tile = side × side = 224 × 224 cm2
Area of the floor = length × breadth = 896 × 672 cm2
Hence, Minimum number of tiles required = Area of floor/area of tile =
= 32 tiles
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