Question

the floor of a room is in shape of square of side 4.8. the floor is to be covered by with square tiles of perimeter 1.2m. find the cost of covering the floor if each tile costs rupee 27​

Answer 1

Answer:

Step-by-step explanation:

The room is a square of a side 4.8m.

∴, Area of the room =4.8²=23.04 m².

Perimeter of the square tiles=4a=1.2

or, a=1.2/4

or, a=0.3 m

∴, Area of the square tiles=0.3²=0.09 m²

∴, no. of tiles required to cover the floor of the room is =23.04/0.09=256

∵, each tile costs Rs. 27;

∴, the total cost =256×27=6912

∴, the cost of covering the floor is Rs. 6912 Ans.

Answer 2

Answer:

Thanks for your question...

Your required answer :

• Side of square = 4.8 m
• Perimeter of square = 4 × a
• Given perimeter of tile = 1.2 metre

So side of tile :

• 4 × a = 1.2
• a =
• $\frac{1.2}{4}$
• a = 0.3m

Area of square :

• a² = 23.04 cm²

Now divide the area of square by area of tile :

• $\frac{23.04}{1.2}$
• 19.2 cm

So the cost of covering the floor if each tile costs rupee 27 :

• 19.2 × 27
• Rs 518.4

Brainliest Please