Math, asked by qa25102003, 1 year ago

The floor of a room is in the shape of a parallelogram in which its adjacent sides are 51 M and 37 M one of its diagonals is 20 m then find the area of the floor of the room and find altitude to the side 51 m

Answers

Answered by pavankumar123
5

Let the two adjacent sides of the parallelogram be a = 51 cm, b = 37 cm Let the length of diagonal be c = 20 cm These two sides and the diagonal forms a triangle semi perimeter, s = (a + b + c) / 2 s = (51 + 37 + 20)/2 = 54 cm By Heron's formula, we have area of triangle, Δ = √s(s - a)(s - b)(s - c) = √[54(54 - 51)(54 - 37)(54 - 20) = √54 x 3 x 17 x 34 = 306 sq cm Area of parallelogram = 2 x area of triangle = 2 x 306 = 612 sq cm
Answered by anushkapatel15
1
612 ***is the answer this question. .! I hope this helps you ✅✔▶⚪⚫

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