Question

The floor of a room is in the shape of a square of a side 4.8 m. The floor is to be covered with square tiles of perimeter 1.2 m. Find the cost of covering the floor if each tile costs rupees 27

Answer 1

The room is a square of a side 4.8m.
∴, Area of the room =4.8²=23.04 m².
Perimeter of the square tiles=4a=1.2
or, a=1.2/4
or, a=0.3 m
∴, Area of the square tiles=0.3²=0.09 m²
∴, no. of tiles required to cover the floor of the room is =23.04/0.09=256
∵, each tile costs Rs. 27;
∴, the total cost =256×27=6912
∴, the cost of covering the floor is Rs. 6912 Ans.

Answer 2

Answer:

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