the floor of a room is in the shape of a square of side 4.8 the floor is to be covered with square tiles of perimeter 1.2 m find the ocost of covering the floor if each tile cost r.s 27
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Answer:
Step-by-step explanation:
per of tile= 1.2m
4x=1.2
x=0.3m
area of tile=x^2
=(0.3)^2
=0.09m^2
area of floor=x^2
=(4.8)^2
=23.04m^2
no of tiles =area of floor/area of 1 tile
=23.04/0.09
=256 tiles
cost os tiling= no of tiles x cost of 1 tile
=256 x 27
=6912 rupees
hope it was some use to you!!!
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