The floor of a room is of dimensions 4 mx 6 m. Tiles of size 10 cm
dimensions 4 m x 6 m. Tiles of size 10 cm x 12 cm have to lay on it.
How many tiles are required to cover the floor completely?
Answers
Answered by
3
Answer:
Area of Room= 6m×4m=24m
1m=100cm
24×100=2400cm
Area of 1 tile= 10cm×12cm=120 cm
Therefore, Tiles requiered to cover the floor=2400/120=20
therefore,Tiles requiered =20
Answered by
5
Step-by-step explanation:
total area of the floor = 400 × 600 cm^2 = 240000 cm^2
Area of each tile = 10 × 12 cm^2 = 120 cm^2
Total no.of.tiles required = total area ÷ area of each tile
= 240000 ÷ 120 = 2000 tiles.
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