Question

The floor of a room measuring 15m by 9m requires 3375 square tiles. Find the measurements of each tile. If the tiles available were twice as long determine the number of tiles that would be required.

Answer 1

Answer:

floor of a room measuring 15m by 9m requires 3375 square tiles. Find the measurements of each tile. If the tiles available were twice as long determine the number of tiles that would be required.

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Answer 2

i) Measurements of tile = 20 cm × 20 cm

ii) The number of tile required if the tiles available were twice as long as the tile is 1688

Given:

The measurements of room is 15 m × 9 m

⇒ 15 m = 15 × 100 = 1500 cm  [∵ 1 m = 100 cm ]

⇒ 9 m = 9 × 100 = 900 cm

Dimensions of room in cm = 1500 cm × 900 cm

The number of tiles required for the room = 3375 square tiles

To find:

i) The measurements of tile and

ii) The number of tiles if the tiles available were twice as long used tile

Solution:

The area of the room = 15 m × 9 m = 135 m²

No. of tiles required for the room = area of the room/ area of tile

⇒ 3375 = 1500 cm × 900 cm / Area of the tile

⇒ 3375 = 1350000 / Area of the tile

⇒  Area of the tile  = 1350000/ 3375 = 400

⇒ Area of square tile = 400 cm²

⇒ side of the tile = $\sqrt{400}$ = 20 cm

i) Measurements of tile = 20 cm × 20 cm

If the length of the tile is increased 20 cm

then length of tile = 20 + 20 = 40cm

⇒ dimensions of tile are 40 cm × 20 cm

area of the tile = 40 cm × 20 cm = 800 cm²

No. of required tiles = Area of room/ area of tile

=  1350000/ 800 = 1687.5

ii) The number of tile required = 1688

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