Physics, asked by xxitzmisscutiepiexx1, 3 months ago

The floor of a room of 7.2 m length and 4 m breadth is to be tiled. How many tiles will be required for this job if each square tile to be used has a side of 30 cm?

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Answers

Answered by Anonymous
17

Answer:

Given

The length (l) of the room is 7.2 m

The breadth (b) of the room is 4 m

The side of the square tiles is 30 cm

To find:

Number of tiles required to fill the floor of the room

Now, converting all given values in cm,

\boxed{1m = 100cm}1m=100cm

Room's length = 7.2 * 100 = 720 cm

Room's breadth = 4 * 100 = 400 cm

Now,

The area of the floor (room) = length * breadth (unit sq.)

= 720 * 400

= 288000 cm sq.

Also,

We have to find the area of the square tiles,

Area of one square tile is = (side)² unit sq.

= (30)²

= 900 cm sq.

Finding the number of tiles required to fill the room,

Number of tiles=900288000

Number of tiles = 320

Hence,

The room required 320 tiles.

Some important notes,

✨♦♦Always check the units. If the units are same then move forward.

✨♦♦But if the units are different, then convert them and make all unit the same.

Answered by Anonymous
9

Given

The length (l) of the room is 7.2 m

The breadth (b) of the room is 4 m

The side of the square tiles is 30 cm

To find:

Number of tiles required to fill the floor of the room

Now, converting all given values in cm,

1m=100cm

Room's length = 7.2 * 100 = 720 cm

Room's breadth = 4 * 100 = 400 cm

Now,

The area of the floor (room) = length * breadth (unit sq.)

= 720 * 400

= 288000 cm sq.

Also,

We have to find the area of the square tiles,

Area of one square tile is = (side)² unit sq.

= (30)²

= 900 cm sq.

Finding the number of tiles required to fill the room,

\bf Number\ of\ tiles = \frac{Area\ of\ the\ room}{Area\ of\ one\ tiles} \\ \bf Number\ of\ tiles = \frac{288000}{900}

Number of tiles = 320

Hence,

The room required 320 tiles.

Some important notes,

✨♦♦Always check the units. If the units are same then move forward.

✨♦♦But if the units are different, then convert them and make all unit the same.

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