the floor of a room of area 43.2 CM square is to be covered with tiles which are in the shape of a parallelogram whose base is 18 cm and corresponding height is 8 cm find the cost of covering the floor if the cost of one tile is rupees 25
Answers
Answer: Question is wrong as area of floor is less than tile area should be in m square
cost for tiles = 0.3 * 25 = Rs. 7.5
If area is in m square then
cost for tiles = 3000 * 25 = Rs. 75000
Step-by-step explanation:
Area of floor = 43.2 cm^2
Area of tile = 18 * 8 = 144 cm^2
Total number of tiles to cover floor = Area of floor / Area of tile
= 43.2 / 144 =0.3
cost for tiles = 0.3 * 25 = Rs. 7.5
If area is in m square then
cost for tiles = 0.3 * 25 = Rs. 7.5
Step-by-step explanation:
Area of floor = 43.2 m^2 = 432000 cm^2
Area of tile = 18 * 8 = 144 cm^2
Total number of tiles to cover floor = Area of floor / Area of tile
= 432000 / 144 =3000
cost for tiles = 3000 * 25 = Rs. 75000