Question

the floor of a room of area 43.2 square metre is to be covered with tiles,which are is the shape of a parallelogram whose base is 18 cm. find the cost of covering the floor if the cost of 1 tile is rupees 25

Answer 1

let number of tiles be n

thus

n * area of tile = total area of floor
n *  18 * 1 = 43.2
n = 2.4

Cost of 1 tiles = 25 Rs
2.4 tiles = 25 * 2.4
            = 60 Rs

Answer 2

The area of a parallelogram 'A' is found by multiplying its base 'b' by its height
'h'.
We can only assume its height is same as its width to cover a square room
 A=b*h
A=18*18 = 324cm^2 = 0.0324m^2
43.2/0.0324 = 1333.33
Since you can only buy full tiles, 1334 would need to be purchased to have enough to cover the full floor.
Cost = 1334*25
The cost would be 33350 rupees.