Question

The floor of a room of area 43.2m2si to be covered with tiles which are in the shape of a parallelogram whose base is 18cm and correspinding height is 8cm find the cost if covering the floor if the cost of one tile is rs25

Answer 1

Answer:

cost = Rs. 75000

Step-by-step explanation:

Area of floor = 43.2 m^2 = 432000 cm^2

Area of tile = 18 * 8 = 144 cm^2

Total number of tiles = 432000/144 = 3000

Total cost of tiles = 3000 * 25 = Rs. 75000

Answer 2

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