Question

the floor of an Auditorium Hall is in the shape of a rhombus such that the length of the two diagonals of the hall at 12 metre and 16 metre find the cost of painting the floor at the rate rupees 6.50 per square metre​

Answer 1

Answer:

q

cost of painting =area of rhombusX6.50 =1/2XD1D2=1/2×12×16X6.50=624

Answer 2

The cost of painting the floor is Rs. 624.

Step-by-step explanation:

Since we have given that

Diagonals = 12 m and 16 m

Area of rhombus is given by

$\dfrac{1}{2}\times d_1\times d_2\\\\=\dfrac{1}{2}\times 12\times 16\\\\=6\times 16\\\\=96\ m^2$

Cost per square m = Rs. 6.50

Total cost would be

$96\times 6.50\\\\=Rs.\ 624$

Hence, the cost of painting the floor is Rs. 624.

# learn more:

The perimeter of the floor of a hall is 250m. if the height is 4 metre find the cost of painting the four walls at rupees 12 per square metre​

https://brainly.in/question/14315959