Question

The floor of an office building consists of 200 rhombus shaped tiles and each of its length of the diagonals are 40 cm and 25 cm. Find the total cost of polishing the floor at 0.45 per sq cm. *
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Answer 1

Answer:

Total cost of polishing the floor is RS.45,000

Answer 2

Step-by-step explanation:

Given: 200 rhombi with diagonals $40cm$ and $25cm$. The cost of polishing is ₹$0.45/sqcm$

To find: The cost of polishing the floor.

For calculation of area of 1 rhombus,

We know that area of a rhombus $= \frac{pq}{2}$,

We know that $p=40$ and $q=25$

Thus,

⇒ $A= \frac{40x25}{2}$

⇒ $A= \frac{1000}{2}$

⇒$A=500 cm^{2}$

Thus, area of 200 rhombi,

⇒$500$ × $200$

⇒$1,00,000cm^{2}$

For calculation of the cost of polishing,

⇒ $1,00,000cm^{2}$ × ₹$0.45$

⇒ ₹$45,000$.

The total cost of polishing the floor is ₹$45,000$.