Question

The floor of building consists of 2000 tiles which are rhombus shaped and each of its diagonals are 40cm and 25 cm in length.Find the total cost of polishing the floor,if the cost per m² is₹5.

(Hint: Find area of 1 tile, then multiply by 2000. After finding area of 2000 tiles, find its cost)​

Answer 1

Answer:

ABCD be a tile, such that BD = 45cm & AC = 30cm

Area of each tile =

2

AC×BD

=

2

45×30

=675cm

2

Area of 3000 tiles = 300×675=2025000cm

2

=202.5m

2

Cost of flooring = Rs.(202.5×20)=Rs.4050

Answer 2

Step-by-step explanation:

Area of 1 tile = 1/2 * d1 * d2 = d1*d2/2

= 40*25/2

= 500 cm²= 5m²

Area of 2000 tiles = 5*2000= 10000 m²

Cost for polishing floor for 1m²= ₹5

Total cost for polishing floor = 5*10000

= ₹ 50,000

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