The floor of building consists of 3000 tiles which are rhombus shaped and each of it's diagonals are 45cm and 30cm in length.find the total cost of polishing the floor, if the cost per meter square is Rs 4
Answers
Answer:
Diagonals of rhombus = 45 cm and 30 cm
Area of rhombus = ½ . d¹.d²
so area = ½ × 45 × 30 cm²
=675cm²
area of 1 tile = 675 cm²
area of 3000 tiles = 3000 ×675
=20,25,000 cm²
cost of per cm² = ₹4
cost of 20,25,000 cm² = 20,25,000 × 4
= 81,00,000
TOTAL COST OF POLISHING THE FLOOR = 81,00,000
Answer:
The cost of polishing is Rs.810.
Step-by-step explanation:
Given :
Tiles = 3000
Diagonal 1 = 45 cm
Diagonal 2 = 30 cm
Rate of polishing = Rs. 4 per sq.m
To Find :
The cost of polishing the floor
Solution :
To get the cost, the area of the floor needs to be multiplied by the rate of polishing.
Area of the floor -
The dimensions are not given, so the area of the room will be =
Area of one tile × Number of tiles
As the tile is a Rhombus, Area of a Rhombus =
⇒
⇒
⇒
⇒ 675 cm²
As the cost is per sq.m, convert the area into sq.m -
⇒ 1 sq.m = 10000 sq.cm
⇒ 675/10000
⇒ 0.0675 m²
Area of the room -
⇒ 0.0675 × 3000
⇒ 202.5 m²
Cost of polishing -
Area of room × Rate of polishing
⇒ 202.5 × 4
⇒ 810
Cost of polishing = Rs. 810
∴ The cost of polishing is Rs.810.