Question

The floor of building consists of 3000 tiles which are rhombus shaped and each of it's diagonals are 45cm and 30cm in length.find the total cost of polishing the floor, if the cost per meter square is Rs 4​

Answer 1

Answer:

Diagonals of rhombus = 45 cm and 30 cm

Area of rhombus = ½ . d¹.d²

so area = ½ × 45 × 30 cm²

=675cm²

area of 1 tile = 675 cm²

area of 3000 tiles = 3000 ×675

=20,25,000 cm²

cost of per cm² = ₹4

cost of 20,25,000 cm² = 20,25,000 × 4

= 81,00,000

TOTAL COST OF POLISHING THE FLOOR = 81,00,000

Answer 2

Answer:

The cost of polishing is Rs.810.

Step-by-step explanation:

Given :

Tiles = 3000

Diagonal 1 = 45 cm

Diagonal 2 = 30 cm

Rate of polishing = Rs. 4 per sq.m

To Find :

The cost of polishing the floor

Solution :

To get the cost, the area of the floor needs to be multiplied by the rate of polishing.

Area of the floor -

The dimensions are not given, so the area of the room will be =

Area of one tile × Number of tiles

As the tile is a Rhombus, Area of a Rhombus =

⇒ $\sf{\dfrac{1}{2} \times (d_1 \times d_2)}}$

⇒ $\sf{\dfrac{1}{2}\times (45\times30)}}$

⇒ $\sf{\dfrac{1}{2}}\times1350$

⇒ 675 cm²

$\rule{300}{1.5}$

As the cost is per sq.m, convert the area into sq.m -

⇒ 1 sq.m = 10000 sq.cm

⇒ 675/10000

⇒ 0.0675 m²

$\rule{300}{1.5}$

Area of the room -

⇒ 0.0675 × 3000

⇒ 202.5 m²

$\rule{300}{1.5}$

Cost of polishing -

Area of room × Rate of polishing

⇒ 202.5 × 4

⇒ 810

Cost of polishing = Rs. 810

∴ The cost of polishing is Rs.810.