Question

The floor of dimension 10m×5m is to be covered with rectangular tiles of dimension 20cm by 5cm find the number of tiles required to cover the floor

Answer 1

covert m into cm
10m= 1000cm
5m= 500cm
no. of tiles= dimension of floor÷ dimension of tiles
= 1000×500/20×5
= 1000 tiles

Answer 2

$in \: meter \: to \: centimeter \\ 10m = 1000cm \\ 5m = 500cm \\ \frac{area \: of \: floor \: }{area \: of \: tiles}$
$\frac{1000 \times 500}{20 \times 5 }$
$= 125000$