the floor of rectangular hall has perimeter 250 m. it's height is 5m . Find the cost of painting its four walls (including doors, windows, etc ) at the rate of ₹8 per sq. m
Answers
Answer:
Step-by-step explanation:
Given :
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- Perimeter of the hall = 250 m
- Height of the hall = 5 m
To Find :
- Cost of painting the four walls at the rate of ₹8 per m² .
Solution :
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- Area of the four walls = Perimeter of the floor × Height
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- We know perimeter of Rectangle → 2(l + b)
- Therefore, substituting the values in it, we get
⟹ 2( l + b ) h
⟹ 250 × 5
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⟹ 1250 m²
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- From the given cost of painting of 1 square metre was ₹8 then cost of painting of the four walls is
= Total area × Cost
⟹ 1250 × 8
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= ₹ 10,000
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As per the Question the cost of painting of the four walls is ₹ 10,000.
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₹ 10,000
Step-by-step explanation:
Solution :
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Area of the four walls = Perimeter of the floor × Height
⠀⠀⠀⠀⠀⠀⠀⠀
We know perimeter of Rectangle → 2(l + b)
Therefore, substituting the values in it, we get
⟹ 2( l + b ) h
⟹ 250 × 5
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⟹ 1250 m²
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From the given cost of painting of 1 square metre was ₹8 then cost of painting of the four walls is
= Total area × Cost
⟹ 1250 × 8
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= ₹ 10,000
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As per the Question the cost of painting of the four walls is ₹ 10,000.
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₹ 10,000