Question

the floor of the building consits 2000 titles which are rhombus shaped and each of its diagonals are 40cm and 25cm . find the total cost of polishing the floors if the cost per m sq=Rs 5​

Answer 1

Step-by-step explanation:

given

total no.of tiles=2000

$\bigstar$area of 1 tile=1/2×d1×d2

=1/2×40×25

=500cm.sq

$\implies$area of 2000 tiles=500×2000

=10,00,000cm.sq

$\bigstar$10,00,000cm.sq = 1000m.sq [100 cm=1m]

$\implies$cost of polishing per m.sq=5Rs

$\implies$cost of polishing 1000m.sq=1000×5

$\large{\boxed{=5000Rs.}}$

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Answer 2

$\blue{\bold{\underline{\underline{Answer:}}}}$

$\green{\tt{\therefore{the \: total \: cost \: of \: polishing \: the \: floors \: is \: 5000 \: RS}}}$

$\orange{\bold{\underline{\underline{Step-by-step\:explanation:}}}}$

$\green{\underline \bold{Given :}}$

$\tt: \implies the \: floor \: of \: the \: building \: consists \: = 2000 \: tiles$

$\tt: \implies the \: diagonals \: of \: the \: rhombus \: are \: 40cm \: and \: 25cm$

$\red{\underline \bold{To \: Find :}}$

$\tt: \implies the \: total \: cost \: of \: polishing \: the \: floor = \: ?$

• Given Question

$\tt: \implies area \: of \: 1 \: = \frac{1}{2} \times d1 \times d2$

$\tt: \implies \frac{1}{2} \times 40 \times 25$

$\tt: \implies500cm.sq$

$\tt: \implies area \: of \: 2000 \: tiles = 500 \times 2000$

$\tt: \implies1</strong><strong>0</strong><strong>,</strong><strong>00</strong><strong>,00</strong><strong>0</strong><strong>$

$\tt \longrightarrow 10</strong><strong>,</strong><strong>00</strong><strong>,</strong><strong>0</strong><strong>0</strong><strong>0</strong><strong>$

$<strong> \tt \longrightarrow 10,00,000cm.sq = 1000m.sq \bigg[100cm = 1m\bigg]$

$\tt \longrightarrow cost - polishing \: per \: m.sq = 5 \: RS$

$\sf \dashrightarrow cost - polishing \: 1000m.sq = 1000 \times 5$

$\green{\tt{\therefore{the \: total \: cost \: of \: polishing \: the \: floors \: is \: 5000 \: RS}}}$