Math, asked by cchrisfranklin160, 7 months ago

the floor of the building consits 2000 titles which are rhombus shaped and each of its diagonals are 40cm and 25cm . find the total cost of polishing the floors if the cost per m sq=Rs 5​

Answers

Answered by legend9divine001
171

Step-by-step explanation:

given

total no.of tiles=2000

\bigstararea of 1 tile=1/2×d1×d2

=1/2×40×25

=500cm.sq

\impliesarea of 2000 tiles=500×2000

=10,00,000cm.sq

\bigstar10,00,000cm.sq = 1000m.sq [100 cm=1m]

\impliescost of polishing per m.sq=5Rs

\impliescost of polishing 1000m.sq=1000×5

\large{\boxed{=5000Rs.}}

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Answered by rohit301486
35

\blue{\bold{\underline{\underline{Answer:}}}}

\green{\tt{\therefore{the \: total \: cost \: of \: polishing \: the \: floors \: is \: 5000 \: RS}}}

\orange{\bold{\underline{\underline{Step-by-step\:explanation:}}}}

\green{\underline \bold{Given :}}

\tt: \implies the \: floor \: of \: the \: building \: consists \:  = 2000 \: tiles

\tt: \implies the \: diagonals \: of \: the \: rhombus \: are \: 40cm \: and \: 25cm

\red{\underline \bold{To \: Find :}}

\tt: \implies the \: total \: cost \: of \: polishing \: the \: floor  =  \: ?

  • Given Question

\tt: \implies area \: of \: 1 \:  =  \frac{1}{2}  \times d1 \times d2

\tt: \implies \frac{1}{2}  \times 40 \times 25

\tt: \implies500cm.sq

\tt: \implies area \: of \: 2000 \: tiles  = 500 \times 2000

\tt: \implies1</strong><strong>0</strong><strong>,</strong><strong>00</strong><strong>,00</strong><strong>0</strong><strong>

 \tt  \longrightarrow 10</strong><strong>,</strong><strong>00</strong><strong>,</strong><strong>0</strong><strong>0</strong><strong>0</strong><strong>

 <strong> \tt  \longrightarrow 10,00,000cm.sq = 1000m.sq \bigg[100cm = 1m\bigg] 

 \tt \longrightarrow cost - polishing \: per \: m.sq = 5 \: RS

\sf \dashrightarrow cost - polishing \: 1000m.sq = 1000 \times 5

\green{\tt{\therefore{the \: total \: cost \: of \: polishing \: the \: floors \: is \: 5000 \: RS}}}

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