Question

The floor of the rectangular hall has perimeter of 250m.if the cost of painting the wall at the rate of 10 per m^2 is Rs 15000.Find height of hall.

Answer 1

Given perimeter of the rectangular floor = 250 m

Hence 2(l + b) = 250

Therefore, (l + b) = 125 --- (1)

Area of four walls, A = 15000/10 = 1500 sq m

That is 2h(l + b) = 1500

2h x 125 = 1500

h = 1500/250 = 6

Thus the height of the hall is 6 m.

Answer 2

Here's your answer!!

__________________________________

It's given that,

Perimeter=250m

$= > 2(l + b) = 250m......(1)$
We know that,

Lateral surface area =

$= > 2(l + b)h......(2)$

If Cost of painting the four walls at rate of 10 per m^2 is ₹15000.

So,

Area of four walls =

$= > \frac{15000}{10} \\ = > 1500 {m}^{2}$

According to the questions :-

$= > 2(l + b)h = 1500$
By putting value of 2(l+b) ,we get ;-


$= > 250 \times h = 1500$
$= > h = \frac{1500}{250} \\ = > h = 6$
Hence,
Height of wall is 6meter

________________________________

Hope it helps you!! :)