Question

The flour in a bag is divided into three portions in the ratio 2:5:7
If the smallest portion weighs 40 kg wt, how much heavier is the largest
portion than the smallest portion?​

Answer 1

Answer:

• 140 kg much heavier is the largest  portion than the smallest portion.

Step-by-step explanation:

Given:

• The flour in a bag is divided into three portions in the ratio 2:5:7.
• The smallest portion weight = 40 kg.

To Find:

• How much heavier is the largest  portion than the smallest portion.

Let the quantity of:

• Smallest = 2x
• Medium = 5x
• Heavier = 7x

Now, according to question,

⇒ 2x = 40

⇒ x = 40/2

⇒ x = 20 kg

So Weights are:

• Smallest = 40 kg
• Medium = 5 × 20 = 100 kg
• Heavier = 7 × 20 = 140 kg

How much heavier is the largest  portion than the smallest portion?​

⇒ Heavier weight - smallest weight

⇒ 140 - 40

⇒ 100 kg.

Hence, 140 kg much heavier is the largest  portion than the smallest portion.

#answerwithquality

#BAL

Answer 2

Answer:

100 kg weight

Step-by-step explanation:

2:5:7=40kg

2x =40

x=40/2

x=20kg

40kg

5 *20 =100

7*20=140

140-40

=100kg wt