Question

The flour in a bag is divided into three portions in the ratio 2: 5:7.
If the smallest portion weighs 40 kg wt, how much heavier is the largest
portion than the smallest portion?​

Answer 1

Answer:

$240 kg$ is the answer

Step-by-step explanation:

Let the largest portion be as x

then according. to the question  

2:5:7 will be assumed as

$2+5+7= 14$

$\frac{2}{14} * x = 40$

$x = 40*\frac{14}{2}$

$x =280kg$

then respectively

112kg

and 80kg

therefore

$280 - 40$

$= 240 kg$

hope it helps

Answer 2

Step-by-step explanation:

let be2x

be5x

be7x

2x+5x+7x=40

14x. =40

x. =40/14

= 2.5kg wt

2x =2x 2.5=5.0kgwt

5x=5x2.5=12.5kg wt

7x=7x2.5=17.5kgwt