The flow rate of liquid metal into the downsprue of a mold = 1 liter/ sec. The cross – sectional area at the top of the sprue
=800mm2, and its length = 175 mm. What area should be used at the base of the sprue to avoid aspiration of the molten metal?
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The flow rate of liquid metal into the downsprue of a mold = 1 liter/ sec. The cross – sectional area at the top of the sprue
=800mm2, and its length = 175 mm. What area should be used at the base of the sprue to avoid aspiration of the molten metal?
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Hey mate...
Here is ur answer..
Flow rate = 1 lt / sec
Also area of cross section = 800 m^2
So pi r^2 = 800
Thus r^2 = 800 * 7/22
r = 16
Thus radius r = 16 mm
Given length H = 175 mm
Thus for height 175 radius can be calculated as
1000 = pi R^2 H
Thus
R^2 = 1000 * 7/22 * 175
R = 236
Thus area needed = pi R^2 = 22/ 7 * 236^2 = 175044
Hope this helps uh...
#sharanaya❤
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