Question

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Answer 1

Answer:

Let distance between Manipur Dispur = x km

Average speed of train from Manipur \( \Large = \frac{x}{4} km/h \)

Average speed of train from Dispur \( \Large = \frac{2x}{7} km/h \)

Let they meet y h after 6 : 00 am.

Then, according to the question,

\( \Large \left(\frac{x}{4} \times y\right)+\frac{2x}{7} \times \left(y-2\right) = x \)

\( \Large \frac{y}{4}+\frac{2 \left(y-2\right) }{7} = 1 \)

7y+8(y-2) = 28

15y = 44

y = \( \Large 15y = 44 \) = 2 h 56 min

Clearly, trains meet 2 h 56 min after 6 : 00 am.

It means the trains meet at 8 : 56 am