Question

the flowchart proof for conjecture is hard for me to understand
thanks in advance for your help

Answer 1

Answer:

☆ ANSWER ☆

GIVEN :

CD BISECTS < ACB

<1 = <2

TO PROVE:

TRIANGLE CDA =~ TRIANGLE CDB

PROOF :

IN TRIANGLE CDA AND CDB

CD = CD ( COMMON )

<1 = <2 ( GIVEN )

< ACD = < BCD ( GIVEN )

THEREFORE ,

BY ASA CONGRUENCE RULE

TRIANGLE CDA =~ TRIANGLE CDB

HOPE IT HELPS