Question

The flux in a coil of 50 turns changes from 0.3 wb to 0.5 wb in seconds. The induced e. M. F. In the coil is ?


Ans= ?

Answer 1

The induced E. M. F. In the coil is 10 V .

Given :

Number of turns , n = 50 .

Initial flux , $\phi_i=0.3\ wb$ .

Final flux , $\phi_f=0.5\ wb$ .

Time taken , t = 1 s .

We know ,

Induced emf is given by :

$e=n \dfrac{d\phi }{ dt }$    .... ( 1 )

Here

$d\phi=\phi_f-\phi_i\\\\d\phi=0.5-0.3\\\\d\phi=0.2\ wb\ .$

Also , $dt$ is given as 1 s .

Putting value of all in equation 1 .

We get :

$e=50\times \dfrac{0.2 }{ 1}\\\\e=10\ V\ .$

Hence , this is the required solution .

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Electromagnetic Induction

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