Question

The flux linked with a coil at any instant t is given by: ∅ = 2t ^2 – t + 1. The magnitude of induced emf at t = 3 sec. is:

Answer 1

Answer:

11V

Explanation:

here

∅ = 2t ^2 – t + 1

Induced emf (e)= -(d∅/dt)

                         = -(4t-1)

at t=3sec

e= -(4*3-1)V

 = -11V

Answer 2

Induced emf ,E = dФ/dt

       Ф=2t²-t+1

The unit of flux is weber (Wb)

Differentiating the equation

E = 4t - 1 +0

   =4t-1

At t=3 secs,  E= 4(3) - 1

                       = 12-1

                        =11 V