Question

The FM station of all india radio ,hassan , broadcast on a frequency of 1020 kilohertz. Calculate the wavelength of the electromagnetic radiation emitted by transmitter

Answer 1

Answer: 294 m

Explanation: Given : frequency = 1020 kHz= 1020000Hz=$1020000s^{-1}$

$1kHz= 1000Hz, 1Hz=1s^{-1}$

$\nu=\frac{c}{\lambda}$

where,

$\nu$=frequency

c= velocity of light=$3\times 10^8m/s$

$\lambda$= wavelength

$1020000s^{-1}=\frac{3\times 10^8m/s}{\lambda}$

$\lambda=294m$

The wavelength of the electromagnetic radiation emitted by transmitter is 294 m.

Answer 2

Given :

Frequency of the F M wave, ν = 1020 kHz = 102 × 10⁴ Hz

To Find:

The wavelength of the electromagnetic radiation emitted by transmitter.

Calculation:

- We know that the relation between frequency and wavelength of a wave is given as:

c = νλ

⇒ λ = c / ν

⇒ λ = (3 × 10⁸) / (102 × 10⁴)

⇒ λ = 294.117 m

⇒ λ ≈ 294.12 m

- So the wavelength of the electromagnetic radiation emitted by transmitter is 294.12 m.