Question

The focal distance of a point on the parabola y2=16x whose ordinate is twice the abscissa is

Answer 1

Answer:

8

Step-by-step explanation:

On parabola, the focal distance is formed between two points which are P and S. The x and y axis at point P are t,2t whereas at Point S they are 4,0.

4a = 16

a = 4

$y^{2}$ = 16x

$(2t)^{2} = 16t$

t = 4

P(t,2t) = P(4,8)

PS = √$(4-4)^{2}$ + $(8-0)^{2}$

PS = 8