Question

The focal length of a biconvex lens of radii of each surface 50 cm and refractive index 1.5, is.The focal length of a biconvex lens of radii of each surface 50 cm and refractive index 1.5, is​

Answer 1

Answer:

The focal length of biconvex lens is 50 cm

Explanation:

By Lens Makers Formula we know that

$\frac{1}{F} = (\mu - 1)(\frac{1}{R_1} - \frac{1}{R_2})$

now we have

$R_1 = +50 cm$

$R_2 = - 50 cm$

$\mu = 1.5$

so we will have

$\frac{1}{F} = (1.5 - 1)(\frac{1}{50} + \frac{1}{50})$

$\frac{1}{F} = 0.5(\frac{2}{50})$

$F = 50 cm$

#Learn

Topic : Lens Maker's Formula

https://brainly.in/question/4950702

Answer 2

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