Question

The focal length of a concave lens is 15 cm .Find the nature and position of a image placed at a distance of 10cm from the lens. in​

Answer 1

Answer:

Since the image distance is positive, the image is real (formed on the right side of lens) at a distance of 3.3 cm. Therefore as per the original scale, (a) Position of image A'B' = 3.3 cm × 5 = 16.5 cm from the lens on opposite side. (b) Nature of image A'B': Real and inverted.

Step-by-step explanation:

Answer 2

Step-by-step explanation:

Given f = - 15 cm, (sign convention) , v = - 10 cm

(∴ image formed by concave lens is virtual)

By using lens formula,

-1/u+1/v=1/f

-1/u-1/10=-1/15

-1/u=1/30

-u=30

u= -30

hence we got the answer