the focal length of a concave mirror is 25 cm and image formed at 35 cm and find the position of object and write the nature of image formed
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Answer:
Focal length, f=15cm
Object distance, u=25cm
Object height, h
0
=4cm
From mirror formula,
f
1
=
v
1
+
u
1
−15
1
=
−25
1
+
v
1
⇒
v
1
=
−15
1
+
25
1
v=−37.5cm
magnification, m=−
u
v
=
h
0
h
i
⇒m=−
−25
(−37.5)
=
4
h
i
h
i
=−
25
37.5×4
h
i
=−6cm
To get a sharp image, v=37.5cm
The image is real, inverted and magnified
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