Question

The focal length of a concave mirror is 30 cm. find the position of the object in front of the mirrors so that the image is three times the size of the object at a distance of 40 cm from the mirror where is the object placed? where would the image be if object moved 20 cm toward the mirror? state reason and also draw ray diagram for new position of the object to justify your answer.ko​

Answer 1

Explanation:

Given,

Focal length, f=−30 cm if u=−x

real ⇒ same side ⇒v=−ve

Magnification, m=uv⇒v=m×u=3×(−x)=−3x

From mirror formula, f1=v1+u1

We get −301=−3x1+−x1⇒301=3x1+3

⇒43x=3⇒x=40 cm

So object should be placed at 40 cm to the mirror.

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