The focal length of a concave mirror is 30cm If the distance of the object from the pole in front of the
mirror so that a the real image three times the size of the object formed is 10x cm, find value of x is
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ANSWER
Given focal length f=30cm object length =30 cm and object distance u= 45 cm.
Thus from mirror formula we get ,
f
1
=
v
1
+
u
1
Here both focal length and object distance lies in front of the mirror so consider them negative,hence the above equation can written as
v
1
=
f
1
−
u
1
v
1
=
uf
u−f
v=
u−f
uf
v=−90
Also we know magnification m=
u
−v
=
h
o
h
i
10x=2×30
x=6cm
Given focal length f=30cm object length =30 cm and object distance u= 45 cm.
Thus from mirror formula we get ,
f
1
=
v
1
+
u
1
Here both focal length and object distance lies in front of the mirror so consider them negative,hence the above equation can written as
v
1
=
f
1
−
u
1
v
1
=
uf
u−f
v=
u−f
uf
v=−90
Also we know magnification m=
u
−v
=
h
o
h
i
10x=2×30
x=6cm
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