The focal length of a concave mirror is 50cm. Where an object be placed so that its image is two times and inverted(a) 75 cm(b) 72 cm(c) 63 cm
(d) 50 cm
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Answered by
105
answer : option (a) 75cm
explanation : focal length of concave mirror, f = -50cm
Let the size of object is h
then, size of image = -2h [ negative because image is inverted ]
now, magnification , m = height of image/height of object = -v/u
or, -2h/h = -v/u
or, v = 2u .....(1)
use formula, 1/v + 1/u = 1/f
or, 1/2u + 1/u = 1/-50
or, 3/2u = -1/50
hence, u = -75cm
explanation : focal length of concave mirror, f = -50cm
Let the size of object is h
then, size of image = -2h [ negative because image is inverted ]
now, magnification , m = height of image/height of object = -v/u
or, -2h/h = -v/u
or, v = 2u .....(1)
use formula, 1/v + 1/u = 1/f
or, 1/2u + 1/u = 1/-50
or, 3/2u = -1/50
hence, u = -75cm
Answered by
9
Answer:
Given,
Focal length, f=50cm
Magnification, m=2
m=uv=2
v=2u
From mirror formula,
f1=v1+u1
f1=2u1+u1
u=23f=23×50=75 cm
Object Is placed at 75cm from the mirror.
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