The focal length of a concave mirror is f and the
distance of the object from the principal focus is a. The magnitude of magnification obtained will be-
(a) f+a/f
(b) f /a
(c) f + a
Answers
Answered by
2
Answer:
The correct option is A fx
We know that
magnification (m)=h′h=−vu
where
h′=height of the imageh=height of the objectv=distance of image from mirroru=distance of object from mirror
⇒v=h′uh

u=f+x (as shown)
Using mirror equation,
1f=1v+1u
Putting value of v in mirror equation
1f=1(h′uh)+1u
Multiplying whole equation by u
uf=hh′+1⇒h′h=fx
hope it's helpful ..
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Answered by
3
Answer:
f+a/f is the your answer
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