Physics, asked by praneethsurya269, 10 months ago

the focal length of a converging lens is 20cm .An object is at 60cm from the lens where will be the image formed​

Answers

Answered by parv1357
3

Answer:

1/f=1/V-1/u

1/20=1/v-1/60

1/20+1/60=1/v

1/80=1/v

v=80

Explanation:

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Answered by bhavani2000life
3

Answer:

Given:

Object Distance (u) = - 60cm

Focal Length (f₁) = 20cm

To find: Image Distance (v)

From the Lens formula,

1/f = 1/v - 1/u

We get, v = f x u/ f + u

= v = 20 x (-60)/ 20 - 60

= 20 x 60/40 = 30cm

⇒ Image Distance = 30cm

∴ The image is formed in between F₁ and 2F₁.

  Nature of the Image is (a) Real (b) Dimenished (c) Inverted

(ii) Given:

Height of the Object () = 2cm

To find: Height of the Image ()

We know that,

=  =  ⇒  = 30/-60 = 1/-2 ⇒  ⇒  = -1cm

∴ Height of the Image is 1cm, which is below the principal axis.

⇒ For more Clarification, you can observe the figure in the Attachment.

Attachments:
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