the focal length of a converging lens is 20cm .An object is at 60cm from the lens where will be the image formed
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3
Answer:
1/f=1/V-1/u
1/20=1/v-1/60
1/20+1/60=1/v
1/80=1/v
v=80
Explanation:
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Answered by
3
Answer:
Given:
Object Distance (u) = - 60cm
Focal Length (f₁) = 20cm
To find: Image Distance (v)
From the Lens formula,
1/f = 1/v - 1/u
We get, v = f x u/ f + u
= v = 20 x (-60)/ 20 - 60
= 20 x 60/40 = 30cm
⇒ Image Distance = 30cm
∴ The image is formed in between F₁ and 2F₁.
Nature of the Image is (a) Real (b) Dimenished (c) Inverted
(ii) Given:
Height of the Object () = 2cm
To find: Height of the Image ()
We know that,
= = ⇒ = 30/-60 = 1/-2 ⇒ ⇒ = -1cm
∴ Height of the Image is 1cm, which is below the principal axis.
⇒ For more Clarification, you can observe the figure in the Attachment.
Attachments:
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