Question

The focal length of a convex lens is
50cm. if an object is kept at a distance
of 75 cm from the lens, then find the
image distance and magnification produced by the lens​

Answer 1

Explanation:

Focal length of = 50 cm

Distance of object = -75 cm

By lens formula:

$\frac{1}{v} - \frac{1}{u} = \frac{1}{f} \\ \frac{1}{v} = \frac{1}{f} + \frac{1}{u} \\ \frac{1}{v} = \frac{1}{50} + \frac{1}{ - 75} \\ \: \: \: \: \: = \frac{3 - 2}{150} \\ \: \: \: \: = \frac{1}{150} \\ \: \: \: \: v= 150cm$

$m = \frac{v}{u} \\ m = \frac{150}{75} \\ m = 2$

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