the focal length of a lens is +0.50m the power of the lens and type are
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A concave lens of focal length 2m
Power of combination P=1.5 dioptre
Power of convex lens having focal length of 0.5m, P1=0.51 dioptre
Using P=P1+P2
∴ 1.5=0.51+P2
We get P2=−0.5 dioptre
Thus focal length of second lens f2=P21
⟹ f2=−0.51=−2m (negative sign implies the lens must be a concave lens)
Thus second lens could be concave lens of focal length 2m.
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