Question

The focal length of concave lens is 20cm.object is located from optic centre is 25cm.find the nature,position,size of the image.

Answer 1

Answer:

So image formed is virtual.

Hence, virtual image is formed at a distance of 11.1 cm in front of the lens.

Explanation:

Focal length   f=−20 cm

Object distance  u=−25 cm

Using    $\frac{1}{v} -\frac{1}{u} =\frac{1}{f}$

            $\frac{1}{v}=\frac{1}{-20}- \frac{1}{25}$

           $\frac{1}{v}=-\frac{9}{100}$

           v=$\frac{-100}{9}$

           v= -11.1

we get   v=−11.1 cm

Since, v is negative. So image formed is virtual.

Hence, virtual image is formed at a distance of 11.1 cm in front of the lens.

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