Question

The focal length of concave mirror is f and object is placed at a distance x from focus what is value of linear magnification.​

Answer 1

Explanation:

MARK AS BRAINLIEST...

Answer 2

Explanation:

${\huge{\bold{\underline{\underline{Answer:}}}}}$

♡ We know mirror formula,

$$\dfrac { 1 }{ f } =\dfrac { 1 }{ v } +\dfrac { 1 }{ u } $$

Given focal length = f and object distance u=f+x

Thus putting the above values in the mirror formula we get

$$\dfrac { 1 }{ -f } -\dfrac { 1 }{ -u } =\dfrac { 1 }{ v } $$

$$\dfrac { 1 }{ v } =\dfrac { 1 }{ -f } -\dfrac { 1 }{ -(f+x) } $$

=

−f(f+x)

(f+x)−f

=

f(f+x)

−x

v=

x

−f(f+x)

Now we magnification m=

u

−v

m=

−(f+x)

−(

x

−f(f+x)

)

=

x

−f

♡

$\huge\boxed{\fcolorbox{red}{purple}{FOLLOW ME!!}}$