Question

The focal length of objective and eye-piece of compound microscope are 1 cm and 5 cm respectively. The microscope magnification is equal to 50. If the distance between two lenses is increased by 2 cm, then the magnification is​

Answer 1

$\huge\blue{solution:}$

fo = 1cm assuming image at infinity

fe = 5cm

M = 50

l = Vo + Ve = 50

Vo/Uo = 25/5 = Vo = Uo

1/Vo - 1/Uo = 1/Fo

1/100Vo - 1/Uo = 2-1

Vo = 9/10Vo = 9

L = 14

l' = 16 = Vo = 11

1/11 - 1/40 = -1

2/4 = Uo = 11/12

M = 12 × 25/5

60 .

hope it helps you ${\overbrace{\underbrace{\green{thanks}}}}$