Question

The focal length of objective
and eye-piece of compound
microscope are 1 cm and 5
cm respectively. The
microscope magnification is
equal to 50. If the distance
between two lenses is
increased by 2 cm, then the
magnification is
31
60
16​

Answer 1

Answer:

f = 1cm

fe = 5cm

M = 50

l = Vo/Uo × 25/5 = Vo= Uo

1/100 Vo - 1/Uo = 1

Vo = 9 Vo/10 = 9

l = 14

l '= 16

= Vo = 11

1/11- 1/40 = -1

2/4 = Uo = 11/12

M = 12 × 25/5

60

hope it helps you

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