The focal length of the eye lens in Huygen's
eye-piece is 3 cm. Calculate i) focal length
of field lens, ii) distance between the
lenses.
O 3 cm & 6 cm resp.
O 9 cm & 3 cm resp.
O 6 cm & 9 cm resp.
O 9 cm & 6 cm resp.
Answers
Answered by
0
Answer:
0 3 is piece of eye 09 cm is calculated by 3 cm
Step-by-step explanation:
09 is distance between the lenses
Answered by
0
Effective focal length, F=3cm
For Huygens eyepiece, if focal length of field lens is f, then effective focal length F= 2 f
=> f=2F=6cm=0.06m
Focal power of field lens = 1f
= 16.7D
O 3 cm & 6 cm resp is the answerr.
Similar questions