Question

The foci of the ellipse 3x² + 2y^2 = 1 are​

Answer 1

Answer:

ANSWER

3x

2

+2y

2

+6x−8y+5=0

⇒

2

(x+1)

2

+

3

(y−2)

2

=1

Therefore, centre is (−1,2) and ellipse is vertical

(∵b>a)

a

2

=2,b

2

=3

Now 2=3(1−e

2

)

⇒e=

3

1

Foci are (−1,2±be) and (−1,2±1).

Hence, the foci are (−1,3) and (−1,1)

The equations of the directrices are y=2±

e

b

⇒y=5 and y=−1