Question

the following aqueous solution in the correct order of decreasing freezing point​

Answer 1

$\huge\underline{\underline{\bf \orange{Solution}}}$

$\large{\rm We \: know \: that-}$

✪$\large{\boxed{\bf \blue{\triangle T_f=K_fim}}}$

Here ,

i = Van't Hoff Factor

m = Molality

${\sf K_f}$ = constant

We can see that ⎯

$\large{\boxed{\bf \blue{\triangle T_f\:\:\:\alpha\:\:\:i} }}$

In this Question ⎯

${\sf \red{Na_2SO_4→2Na^+ + SO_4^{-2}}}$

No. of ions in this reaction is = 3

⛬ i = 3

${\sf \red{BaCl_2→Ba^{+2}+2Cl^-}}$

No. of ions in this reaction is = 3

⛬ i = 3

${\sf\red{ KCl→K^+ + Cl^-}}$

No. of ions in this reaction is = 2

⛬ i = 2

Thus , ${\sf \blue{Na_2SO_5\:and\:BaCl_2}}$ exhibit largest freezing depression due to the highest value of i .

Therefore Correct Decreasing Order will be ➝

Option (4)

${\sf \red{0.1M\:Na_2SO_4\:,0.2M\:BaCl_2\:,0.2M\:KCl} }$

Answer 2

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