The following are the electrical appliances used in house per day five 100W lamps used for 4 hours two 60W lamps used for 4 hours one 150W refrigator used for 24 hours one 200w television set for three hours one 750W iron for 0.5 hours and one 3kW electric cooker for 2 hours calculate the electrical energy consumed each day
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energy =p×time here p in watt and t in sec for five lamp 500w and 2 lamp 120w so total 620 w so E1= 620×4×60×60,E1=8928000joule , E2 = 150×24×60×60,E2=12960000 joule , E3= =200×3×60×60,E3=2160000joule ,E4=750×0.5×60×60,E4=5400000joule, E5= 3×1000×2×60×60,E5=21600000joule add all Et=8928000+12960000+2160000+5400000+21600000,Et=8928×10^3+12960×10^3+2160×10^3+5400×10^3+21600×10^3 ,, 10^3 is common then Et=51048×10^3 joule ans
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