Math, asked by py9305237265, 8 months ago

The following are the shapes of different flower beds in a
A flooring tile has the shape of a parallelogram whose base is 24 cm and the correspondi
height is 10 cm. How many such tiles are required to cover a floor of area 1080 m.​

Answers

Answered by niki5085
1

Answer:

Required No. of tiles = 45000

Step-by-step explanation:

Base of tile = 24 cm

Height of tile = 10 cm

Required no. of tiles which is required to cover a floor of area 1080 m^2:

= Area of floor

Area of tile

= 1080 m^2

b× h cm^2

= 1080 × 10000 cm^2

24 × 10 cm^2

= 45 × 1000

= 45000 tiles.

Answered by mehreennaikoo123
1

Total area of room = 1080m²

Base of "one" tile = 24cm

Height of "one" tile = 10cm

Area of "one" tile = Base×height

\huge\purple{24 \times 10}

\huge\purple{240 {cm}^{2} }

\huge\purple{0.024 {m}^{2} }

\red{no. \: of \: tiles \:  =  \frac{area \: of \: room}{area \: of \: one \: tile} }

\huge\orange{ \frac{1080}{0.024} }

\pink{so... \: 45000 \:tiles \: are \: needed }

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