Question

The following bar graph summarizes the weather conditions in Crayonton for each day this month so far. Based on this data, what is a reasonable estimate of the probability that it is sunny tomorrow? Choose the best answer. Choose 1 answer: Choose 1 answer:

Answer 1

${\huge{\bold{\underline{Answer:-}}}}$

Probability

The Probability of an event is calculated with the simple logical formula:

\textsf{Probability of an event} = \dfrac{\textsf{Number of favourable occurences of event}}{\textsf{Total number of possible events}}Probability of an event=Total number of possible eventsNumber of favourable occurences of event

Here, the Bar Graph shows the data in Crayonton. The data in tabular format is this:

\begin{gathered}\begin{tabular}{|c|c|}\cline{1-2}\tt Weather Condition &\tt Number of days \\\cline{1-2}\sf Sunny & \sf 3 \\\sf Cloudy & \sf 5 \\\sf Rainy & \sf 2 \\ \sf Snowy & \sf 2 \\ \cline{1-2}\end{tabular}\end{gathered}

Suppose Event A is that it is Sunny tomorrow in Crayonton. We make this prediction based on the past data.

First, we need the total number of events.

Total Number of Events = 3 Sunny + 5 Cloudy + 2 Rainy + 2 Snowy = 12 Events

Thus, Total Number of Events is 12.

Out of that, the number of favourable events, which is Sunny in our case, are 3.

So, Number of favourable occurrences of Event A = 3

This is simply because there have been 3 Sunny Days out of 12.

So, Probability of Event A, denoted as P(A), is:

\begin{gathered}\sf P(A) = \dfrac{3}{12} = \dfrac{1}{4} \\\\\\ \implies \sf P(A) = \dfrac{1}{4} \times 100\ \% \\\\\\ \implies \Large\boxed{\sf P(A) = 25\ \%}\end{gathered}P(A)=123=41⟹P(A)=41×100 %⟹P(A)=25 %

Thus,

The Probability that it will be sunny tomorrow in Crayonton is (d) 25 %