The following choices are available:
5 different sandwiches
4 different desserts
6 different drinks
2 of the desserts are sugar-free
3 of the drinks are sugar-free
Work out the probability as a fraction that both the dessert and the drink are sugar- free.
Answers
Answered by
3
Answer:
14400
Step-by-step explanation:
Given that. sandwiche=5
deserts=4
drinks=6
sugar free deserts=2
sugar free drinks=3
so probablity= (5!)×(4*3/2*1)×(6*5*4/3*2*1)
= (5*4*3*2*1)×(12/2)×(120/6)
= (120)×(6)×(20)
= 120×6×20
= 14400
Answered by
1
Answer:
a) 120
b)6/120
Step-by-step explanation:
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